Lab report template template

A practical write-up frame: aim, hypothesis, apparatus list and diagram box, chemicals and hazards, method, results table, calculations, conclusion and evaluation, with a titration worked in grey as the example.

What the template shows

• Lab report
• Name ____________ Class ______ Date ________ Partner(s) ______________
• Grey text is a worked example (titration of HCl with 0.100 M NaOH): example values only, replace them with your own.
• e.g. To determine the concentration of a hydrochloric acid solution by titration against standard 0.100 mol dm⁻³ NaOH.
• e.g. The acid is about 0.1 mol dm⁻³, so 25.0 cm³ should need about 25 cm³ of NaOH (1 : 1 reaction).
• e.g. 50 cm³ burette, 25.0 cm³ pipette and filler, 250 cm³ conical flask, white tile, funnel, clamp stand
• Labelled diagram of the set-up
• Chemicals and hazards
• irritant: eyes and skin
• goggles; wash spills with water
• phenolphthalein in ethanol
• no flames nearby
• Numbered steps in the past tense, passive voice: “25.0 cm³ of acid was pipetted into…”.
• Units in the headings; readings to ±0.05 cm³. The first (rough) row is the example.
• Final reading / cm³
• Initial reading / cm³
• Mean of concordant titres (within 0.10 cm³) = ________ cm³
• NaOH + HCl → NaCl + H₂O (1 : 1)
• n(NaOH) = c × V = 0.100 mol dm⁻³ × 0.02470 dm³ = 2.47 × 10⁻³ mol
• n(HCl) = n(NaOH) = 2.47 × 10⁻³ mol
• c(HCl) = n / V = 2.47 × 10⁻³ mol ÷ 0.02500 dm³ = 0.0988 mol dm⁻³
• Answer the aim with the number, its units and sensible significant figures; say whether the hypothesis was supported.
• Evaluation and errors
• e.g. Burette: 2 readings × ±0.05 cm³ = ±0.10 cm³ → 0.10 / 24.70 × 100 = 0.40 %. Random: judging the end point; systematic: pipette not rinsed with the acid. Improvement: rinse, swirl, add dropwise near the end point.

Drawn with 48 shapes – every one editable in MolDraw.

Sources

• NCERT, Laboratory Manual Chemistry, Class XII Textbook
• Vogel's Textbook of Practical Organic Chemistry, 5th ed., Longman 1989 Textbook