Overall reaction
R–CO–CH₃ + 3 I₂ + 4 NaOH → R–COO⁻Na⁺ + CHI₃↓ + 3 NaI + 3 H₂O
A methyl ketone is triiodinated in base, then cleaved to a carboxylate and CHI₃.
Methyl ketones (CH₃CO–) and alcohols that oxidise to them (CH₃CH(OH)–) react with iodine and sodium hydroxide to give a yellow precipitate of iodoform, CHI₃. The methyl group is iodinated three times through enolates, then hydroxide attacks the carbonyl and CI₃⁻ leaves as a carbanion, giving a carboxylate one carbon shorter.
R–CO–CH₃ + 3 I₂ + 4 NaOH → R–COO⁻Na⁺ + CHI₃↓ + 3 NaI + 3 H₂O
A methyl ketone is triiodinated in base, then cleaved to a carboxylate and CHI₃.
Each step is checked electron by electron: the curly arrows give exactly the structures drawn.
Iodine/NaOH oxidises ethanol to acetaldehyde, CH₃CHO, which has the CH₃–C=O group.
After three iodinations, CI₃⁻ is stabilised by the three iodines and is a good enough leaving group from the tetrahedral intermediate.
No. The carboxylate is not enolised under the conditions.
The button above opens the complete figure — overall reaction, numbered mechanism and key points — as ordinary editable structures. Change substituents, recolour atoms, or export a PNG, SVG or chemfig code for notes and slides. The same figure is in the Templates panel under Name reactions.